Wie kann ich Ordnernamen stapelweise von einem Datumsformat in ein anderes konvertieren?


10

Ich habe eine große Anzahl von Ordnern, die wie folgt benannt sind:

10 Aug 2010  15 Sep 2010  20 Jun 2010  25 Jul 2010  6 Nov 2010
10 Sep 2010  16 Aug 2010  20 Mar 2010  26 Aug 2010  6 Oct 2010
11 Apr 2010  16 Jun 2010  21 Jun 2010  28 Aug 2010  7 Apr 2010
12 Aug 2010  16 Oct 2010  21 Mar 2010  28 Feb 2010  7 Aug 2010
13 May 2010  17 Apr 2010  22 Feb 2010  28 Jun 2010  7 Jun 2010
14 Aug 2010  17 Aug 2010  23 Jul 2010  28 Mar 2010  8 Apr 2010
14 Jun 2010  18 Aug 2010  24 Jul 2010  29 Mar 2010  8 Aug 2010
15 Aug 2010  19 Aug 2010  24 Nov 2010  30 Aug 2010  8 Jul 2010
15 Jul 2010  4 Apr 2010  25 Apr 2010  6 May 2010   8 Sep 2010

Ich möchte, dass sich das Datumsformat wie folgt ändert:

2010-04-04  2010-05-03
2010-06-06  2010-07-02
2010-07-05  2010-09-01
2010-09-04  2010-09-05
2010-11-01

Wie kann ich viele Ordner im Stapel von DD MMM YYYY in YYYY-MM-DD umbenennen?

12

Somewhat to my own surprise, it looks like our old friend prename (a.k.a rename on some systems) can do that - with a little wrangling:

$ prename -vn -- '
  BEGIN{use Time::Piece};
  s/\d+ \w+ \d+/Time::Piece->strptime($&, "%d %b %Y")->strftime("%Y-%m-%d")/e
' *
10 Aug 2010 renamed as 2010-08-10
8 Sep 2010 renamed as 2010-09-08

Alternatively, using GNU date

dirs=( ?\ ???\ ???? ??\ ???\ ???? ) # matches D MMM YYYY and DD MMM YYYY

for d in "${dirs[@]}"; do mv -v -- "$d" "$(date '+%Y-%m-%d' -d "$d")"; done

Testing with an echo (equivalent to prename's -n flag):

$ for d in "${dirs[@]}"; do echo mv -v -- "$d" "$(date '+%Y-%m-%d' -d "$d")"; done
mv -v -- 8 Sep 2010 2010-09-08
mv -v -- 10 Aug 2010 2010-08-10

Note that parsing of dates can be locale dependent.


6

Here is a Python script that can do the renaming using the datetime module:

#!/usr/bin/env python

from datetime import datetime
import os
import os.path
import sys


def main(target):
    dir_path = os.path.abspath(target)
    for i in os.listdir(target):
        old_name = os.path.join(dir_path, i)
        d = datetime.strptime(i, '%d %b %Y').strftime('%Y-%m-%d')
        new_name = os.path.join(dir_path, d)
        os.rename(old_name, new_name)

if __name__ == '__main__':
    main(sys.argv[1])

Let's call the script rename.py. To use the script, first make it executable by running chmod +x rename.py and then running ./rename.py parent_dir where parent_dir is the parent directory containing all the directories whose names you want to change.


9

The GNU date command is very good at converting between different date formats. For example:

$ date -d '17 Aug 2010' +%F
2010-08-17

With that in mind, if the only things in your target directory are the subdirectories you want to rename, you can simply do:

for d in *; do mv "$d" "$(date -d "$d" +%F)"; done

If you want to specify directories only, use:

for dir in */; do d=${dir%%/}; mv "$d" "$(date -d "$d" +%F)"; done

And to match only directories whose name starts with a number:

for dir in [0-9]*/; do d=${dir%%/}; mv "$d" "$(date -d "$d" +%F)"; done

4

Here is a Ruby script that does this same thing. Put this into the directory where all those directory resides.

#!/usr/bin/env ruby

require 'time'

Dir.glob('*').select do |f|
    if File.directory? f
        time = Time.parse(f.to_s)
        File.rename(f, time.strftime("%Y-%m-%d"))
    end
end

Use chmod +x rename.rb and ./rename.rb to rename the directories


0

if you want a good GUI solution try pyrenamer easy and very configurable